What are the solutions to the equation solvefor x,y^2=12x^2 ?

The solutions to the equation solvefor x,y^2=12x^2 are x= y/(2sqrt(3)),x=-y/(2sqrt(3))

Find the zeros of solvefor x,y^2=12x^2

The zeros of solvefor x,y^2=12x^2 are x= y/(2sqrt(3)),x=-y/(2sqrt(3))

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solve for

x, y^{2} = 12 x^{2}

x = \frac{y}{2 3}, x = - \frac{y}{2 3}

Solution steps

y^{2} = 12 x^{2}

Switch sides

12 x^{2} = y^{2}

Divide both sides by

12

x^{2} = \frac{y ^{2}}{12}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{y ^{2}}{12}, x = - \frac{y ^{2}}{12}

Simplify

\frac{y ^{2}}{12} : \frac{y}{2 3}

Simplify

- \frac{y ^{2}}{12} : - \frac{y}{2 3}

x = \frac{y}{2 3}, x = - \frac{y}{2 3}

6 x - 2 x^{2} = 10

225 x^{2} - 16 = 33

x^{2} + 5 x = 14

x^{2} - x + 18 = - 8 x + 8

2 (x + 2)^{2} = 64

What are the solutions to the equation solvefor x,y^2=12x^2 ?
The solutions to the equation solvefor x,y^2=12x^2 are x= y/(2sqrt(3)),x=-y/(2sqrt(3))
Find the zeros of solvefor x,y^2=12x^2
The zeros of solvefor x,y^2=12x^2 are x= y/(2sqrt(3)),x=-y/(2sqrt(3))