What are the solutions to the equation 2(x+2)^2=64 ?

The solutions to the equation 2(x+2)^2=64 are x=4sqrt(2)-2,x=-4sqrt(2)-2

Find the zeros of 2(x+2)^2=64

The zeros of 2(x+2)^2=64 are x=4sqrt(2)-2,x=-4sqrt(2)-2

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2 (x + 2)^{2} = 64

x = 42 - 2, x = - 42 - 2

Decimal Notation

x = 3.65685 \dots, x = - 7.65685 \dots

Solution steps

2 (x + 2)^{2} = 64

Divide both sides by

2

(x + 2)^{2} = 32

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 32 : x = 42 - 2

Solve

x + 2 = - 32 : x = - 42 - 2

The solutions to the quadratic equation are:

x = 42 - 2, x = - 42 - 2

2 x^{2} - 8 x - 10 = 0

x^{2} - (m + n) x + mn = 0

x^{2} - x + \frac{1}{4} = 25

9 r^{2} - 25 = 0

2 (2 x - 5) - x^{2} + 17 x = 16 \cdot 4

What are the solutions to the equation 2(x+2)^2=64 ?
The solutions to the equation 2(x+2)^2=64 are x=4sqrt(2)-2,x=-4sqrt(2)-2
Find the zeros of 2(x+2)^2=64
The zeros of 2(x+2)^2=64 are x=4sqrt(2)-2,x=-4sqrt(2)-2