What are the solutions to the equation 9r^2-25=0 ?

The solutions to the equation 9r^2-25=0 are r= 5/3 ,r=-5/3

Find the zeros of 9r^2-25=0

The zeros of 9r^2-25=0 are r= 5/3 ,r=-5/3

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9 r^{2} - 25 = 0

r = \frac{5}{3}, r = - \frac{5}{3}

Decimal Notation

r = 1.66666 \dots, r = - 1.66666 \dots

Solution steps

9 r^{2} - 25 = 0

Move

25

to the right side

9 r^{2} = 25

Divide both sides by

9

r^{2} = \frac{25}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = \frac{25}{9}, r = - \frac{25}{9}

\frac{25}{9} = \frac{5}{3}

- \frac{25}{9} = - \frac{5}{3}

r = \frac{5}{3}, r = - \frac{5}{3}

2 (2 x - 5) - x^{2} + 17 x = 16 \cdot 4

5 x (x + 1) = 15

- 3 (x - 2) - 4 x^{2} = 0

x^{2} - 8 x - 8 = 0

4 x^{2} + 4 x + 1 = 0

What are the solutions to the equation 9r^2-25=0 ?
The solutions to the equation 9r^2-25=0 are r= 5/3 ,r=-5/3
Find the zeros of 9r^2-25=0
The zeros of 9r^2-25=0 are r= 5/3 ,r=-5/3