What are the solutions to the equation completesquare 4x^2+4x+1=0 ?

The solutions to the equation completesquare 4x^2+4x+1=0 are x=-1/2

Find the zeros of completesquare 4x^2+4x+1=0

The zeros of completesquare 4x^2+4x+1=0 are x=-1/2

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4 x^{2} + 4 x + 1 = 0

x = - \frac{1}{2}

Decimal Notation

x = - 0.5

Solution steps

4 x^{2} + 4 x + 1 = 0

Move

1

to the right side

4 x^{2} + 4 x = - 1

Divide both sides by

4

\frac{4 x ^{2} + 4 x}{4} = \frac{- 1}{4}

x^{2} + x = - \frac{1}{4}

Rewrite in the form

(x + a)^{2} = b

(x + \frac{1}{2})^{2} = 0

Solve

x + \frac{1}{2} = 0 : x = - \frac{1}{2}

The solution to the quadratic equation is:

x = - \frac{1}{2}

(2 x - 8) (2 x + 8) = 55

t^{2} + 8 t + 16 = 0

0 = 0.03 q^{2} + 35 q - 712

4 x^{2} - 250 = 0

4 x^{2} - 6 = 2 x

What are the solutions to the equation completesquare 4x^2+4x+1=0 ?
The solutions to the equation completesquare 4x^2+4x+1=0 are x=-1/2
Find the zeros of completesquare 4x^2+4x+1=0
The zeros of completesquare 4x^2+4x+1=0 are x=-1/2