What are the solutions to the equation (x-6)(x-1)=4x-18 ?

The solutions to the equation (x-6)(x-1)=4x-18 are x=8,x=3

Find the zeros of (x-6)(x-1)=4x-18

The zeros of (x-6)(x-1)=4x-18 are x=8,x=3

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(x - 6) (x - 1) = 4 x - 18

x = 8, x = 3

Solution steps

(x - 6) (x - 1) = 4 x - 18

Expand

(x - 6) (x - 1) : x^{2} - 7 x + 6

x^{2} - 7 x + 6 = 4 x - 18

Move

18

to the left side

x^{2} - 7 x + 24 = 4 x

Move

4 x

to the left side

x^{2} - 11 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot 24 = 5

x_{1, 2} = \frac{- ( - 11 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 11 ) - 5}{2 \cdot 1}

x = \frac{- ( - 11 ) + 5}{2 \cdot 1} : 8

x = \frac{- ( - 11 ) - 5}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 8, x = 3

k^{2} - 3 k - 4 = 0

(x + 3)^{2} = 3 - x

x^{2} + 14 x + 64 = 0

r^{2} - 32 = 0

9 x - 3 x^{2} = 6

What are the solutions to the equation (x-6)(x-1)=4x-18 ?
The solutions to the equation (x-6)(x-1)=4x-18 are x=8,x=3
Find the zeros of (x-6)(x-1)=4x-18
The zeros of (x-6)(x-1)=4x-18 are x=8,x=3