What are the solutions to the equation (x+7)^2-288=0 ?

The solutions to the equation (x+7)^2-288=0 are x=12sqrt(2)-7,x=-12sqrt(2)-7

Find the zeros of (x+7)^2-288=0

The zeros of (x+7)^2-288=0 are x=12sqrt(2)-7,x=-12sqrt(2)-7

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(x + 7)^{2} - 288 = 0

x = 122 - 7, x = - 122 - 7

Decimal Notation

x = 9.97056 \dots, x = - 23.97056 \dots

Solution steps

(x + 7)^{2} - 288 = 0

Move

288

to the right side

(x + 7)^{2} = 288

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 7 = 288 : x = 122 - 7

Solve

x + 7 = - 288 : x = - 122 - 7

The solutions to the quadratic equation are:

x = 122 - 7, x = - 122 - 7

5 x^{2} - 23 x = - 12

4 x^{2} - 4 x + 7 x - 7 = 2

8 x + 2 + 5 x^{2} = 4

2 x (9 - 5 x) = - 5 x (2 - 3 x)

(3 y - 5) (2 y + 7) = 0

What are the solutions to the equation (x+7)^2-288=0 ?
The solutions to the equation (x+7)^2-288=0 are x=12sqrt(2)-7,x=-12sqrt(2)-7
Find the zeros of (x+7)^2-288=0
The zeros of (x+7)^2-288=0 are x=12sqrt(2)-7,x=-12sqrt(2)-7