What are the solutions to the equation x(x+6)=8+4x ?

The solutions to the equation x(x+6)=8+4x are x=2,x=-4

Find the zeros of x(x+6)=8+4x

The zeros of x(x+6)=8+4x are x=2,x=-4

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x (x + 6) = 8 + 4 x

x = 2, x = - 4

Solution steps

x (x + 6) = 8 + 4 x

Expand

x (x + 6) : x^{2} + 6 x

x^{2} + 6 x = 8 + 4 x

Move

4 x

to the left side

x^{2} + 2 x = 8

Move

8

to the left side

x^{2} + 2 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 8) = 6

x_{1, 2} = \frac{- 2 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 6}{2 \cdot 1}, x_{2} = \frac{- 2 - 6}{2 \cdot 1}

x = \frac{- 2 + 6}{2 \cdot 1} : 2

x = \frac{- 2 - 6}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 2, x = - 4

x^{2} = \frac{- 7 x - 3}{2}

2 q^{2} + 9 q + 3 = 4

2 x (x + 4) = (x - 3)^{2}

x (x + 3) = 16

y, 5 x^{3} - x y^{2} + 3 y = C

What are the solutions to the equation x(x+6)=8+4x ?
The solutions to the equation x(x+6)=8+4x are x=2,x=-4
Find the zeros of x(x+6)=8+4x
The zeros of x(x+6)=8+4x are x=2,x=-4