What are the solutions to the equation x^2+ax=20a^2 ?

The solutions to the equation x^2+ax=20a^2 are x=4a,x=-5a

Find the zeros of x^2+ax=20a^2

The zeros of x^2+ax=20a^2 are x=4a,x=-5a

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x^{2} + a x = 20 a^{2}

x = 4 a, x = - 5 a

Solution steps

x^{2} + a x = 20 a^{2}

Move

20 a^{2}

to the left side

x^{2} + a x - 20 a^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- a \pm a ^{2} - 4 \cdot 1 \cdot ( - 20 a ^{2} )}{2 \cdot 1}

Simplify

a^{2} - 4 \cdot 1 \cdot (- 20 a^{2}) : 9 a

x_{1, 2} = \frac{- a \pm 9 a}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- a + 9 a}{2 \cdot 1}, x_{2} = \frac{- a - 9 a}{2 \cdot 1}

x = \frac{- a + 9 a}{2 \cdot 1} : 4 a

x = \frac{- a - 9 a}{2 \cdot 1} : - 5 a

The solutions to the quadratic equation are:

x = 4 a, x = - 5 a

x^{2} - 4 x + 61 = 10 x + 13

x, 5 x y - x^{2} y + y^{2} = 0

x^{2} + 4 x + 1 + 5 = 0

x, 16 x^{2} - y^{2} = 0

x, y = x^{2} - 7 x + 10

What are the solutions to the equation x^2+ax=20a^2 ?
The solutions to the equation x^2+ax=20a^2 are x=4a,x=-5a
Find the zeros of x^2+ax=20a^2
The zeros of x^2+ax=20a^2 are x=4a,x=-5a