What are the solutions to the equation x^2+4x+1+5=0 ?

The solutions to the equation x^2+4x+1+5=0 are x=-2+sqrt(2)i,x=-2-sqrt(2)i

Find the zeros of x^2+4x+1+5=0

The zeros of x^2+4x+1+5=0 are x=-2+sqrt(2)i,x=-2-sqrt(2)i

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x^{2} + 4 x + 1 + 5 = 0

x = - 2 + 2 i, x = - 2 - 2 i

Solution steps

x^{2} + 4 x + 1 + 5 = 0

Refine

x^{2} + 4 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 6 : 22 i

x_{1, 2} = \frac{- 4 \pm 2 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 2 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 2 i}{2 \cdot 1}

x = \frac{- 4 + 2 2 i}{2 \cdot 1} : - 2 + 2 i

x = \frac{- 4 - 2 2 i}{2 \cdot 1} : - 2 - 2 i

The solutions to the quadratic equation are:

x = - 2 + 2 i, x = - 2 - 2 i

x, 16 x^{2} - y^{2} = 0

x, y = x^{2} - 7 x + 10

6 x^{2} = 12 - x

\frac{t ^{2} - 1}{3} = t^{2} - 5

175 t^{2} - 252 = 0

What are the solutions to the equation x^2+4x+1+5=0 ?
The solutions to the equation x^2+4x+1+5=0 are x=-2+sqrt(2)i,x=-2-sqrt(2)i
Find the zeros of x^2+4x+1+5=0
The zeros of x^2+4x+1+5=0 are x=-2+sqrt(2)i,x=-2-sqrt(2)i