What are the solutions to the equation 175t^2-252=0 ?

The solutions to the equation 175t^2-252=0 are t= 6/5 ,t=-6/5

Find the zeros of 175t^2-252=0

The zeros of 175t^2-252=0 are t= 6/5 ,t=-6/5

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175 t^{2} - 252 = 0

t = \frac{6}{5}, t = - \frac{6}{5}

Decimal Notation

t = 1.2, t = - 1.2

Solution steps

175 t^{2} - 252 = 0

Move

252

to the right side

175 t^{2} = 252

Divide both sides by

175

t^{2} = \frac{36}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = \frac{36}{25}, t = - \frac{36}{25}

\frac{36}{25} = \frac{6}{5}

- \frac{36}{25} = - \frac{6}{5}

t = \frac{6}{5}, t = - \frac{6}{5}

x, f (a + 1) = 3 x^{2} - x + 2

17 + 2 x^{2} - 9 x = 17 - 3 x

x^{2} = - 3 x + 28

6 x^{2} + 3 = 12 x - 5

x (- 18 + 9 x) - 14 = - 1

What are the solutions to the equation 175t^2-252=0 ?
The solutions to the equation 175t^2-252=0 are t= 6/5 ,t=-6/5
Find the zeros of 175t^2-252=0
The zeros of 175t^2-252=0 are t= 6/5 ,t=-6/5