What is factor 2x^2+3x-20 ?

The solution to factor 2x^2+3x-20 is (2x-5)(x+4)

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factor 2x^2+3x-20

factor

2 x^{2} + 3 x - 20

(2 x - 5) (x + 4)

Solution steps

2 x^{2} + 3 x - 20

Break the expression into groups

= (2 x^{2} - 5 x) + (8 x - 20)

Factor out

x

from

2 x^{2} - 5 x : x (2 x - 5)

Factor out

4

from

8 x - 20 : 4 (2 x - 5)

= x (2 x - 5) + 4 (2 x - 5)

Factor out common term

2 x - 5

= (2 x - 5) (x + 4)

x = - 6 x^{2} + 384

2 x - 1 < 4 and - 5 x - 3 > - 3

\frac{3 x ^{7} y ^{5}}{x y ^{7}}

\frac{( x - 1 )}{x + 1} < 1

\frac{2}{5} \cdot \frac{1}{2}