What are the solutions to the equation 17+2x^2-9x=17-3x ?

The solutions to the equation 17+2x^2-9x=17-3x are x=3,x=0

Find the zeros of 17+2x^2-9x=17-3x

The zeros of 17+2x^2-9x=17-3x are x=3,x=0

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17 + 2 x^{2} - 9 x = 17 - 3 x

x = 3, x = 0

Solution steps

17 + 2 x^{2} - 9 x = 17 - 3 x

Move

3 x

to the left side

17 + 2 x^{2} - 6 x = 17

Move

17

to the left side

2 x^{2} - 6 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 6)^{2} - 4 \cdot 2 \cdot 0 = 6

x_{1, 2} = \frac{- ( - 6 ) \pm 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6}{2 \cdot 2}, x_{2} = \frac{- ( - 6 ) - 6}{2 \cdot 2}

x = \frac{- ( - 6 ) + 6}{2 \cdot 2} : 3

x = \frac{- ( - 6 ) - 6}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = 3, x = 0

x^{2} = - 3 x + 28

6 x^{2} + 3 = 12 x - 5

x (- 18 + 9 x) - 14 = - 1

x - (x + 2) (4 - x) = (x + 1) 2 - 3

6 x^{2} - 6 x = 2

What are the solutions to the equation 17+2x^2-9x=17-3x ?
The solutions to the equation 17+2x^2-9x=17-3x are x=3,x=0
Find the zeros of 17+2x^2-9x=17-3x
The zeros of 17+2x^2-9x=17-3x are x=3,x=0