What are the solutions to the equation (x-4)^2=3x-12 ?

The solutions to the equation (x-4)^2=3x-12 are x=7,x=4

Find the zeros of (x-4)^2=3x-12

The zeros of (x-4)^2=3x-12 are x=7,x=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x - 4)^{2} = 3 x - 12

x = 7, x = 4

Solution steps

(x - 4)^{2} = 3 x - 12

Expand

(x - 4)^{2} : x^{2} - 8 x + 16

x^{2} - 8 x + 16 = 3 x - 12

Move

12

to the left side

x^{2} - 8 x + 28 = 3 x

Move

3 x

to the left side

x^{2} - 11 x + 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 28}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot 28 = 3

x_{1, 2} = \frac{- ( - 11 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 11 ) - 3}{2 \cdot 1}

x = \frac{- ( - 11 ) + 3}{2 \cdot 1} : 7

x = \frac{- ( - 11 ) - 3}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

x = 7, x = 4

(2 x - 1)^{2} = 36

100 = q^{2}

x, f (x + 1) = 3 x^{2} - x + 5

x, ln (y) = a x^{2} + b

x^{2} + 6 x + 8 = 24

What are the solutions to the equation (x-4)^2=3x-12 ?
The solutions to the equation (x-4)^2=3x-12 are x=7,x=4
Find the zeros of (x-4)^2=3x-12
The zeros of (x-4)^2=3x-12 are x=7,x=4