What are the solutions to the equation -2x^2-14x+5=0 ?

The solutions to the equation -2x^2-14x+5=0 are x=-(7+sqrt(59))/2 ,x=(sqrt(59)-7)/2

Find the zeros of -2x^2-14x+5=0

The zeros of -2x^2-14x+5=0 are x=-(7+sqrt(59))/2 ,x=(sqrt(59)-7)/2

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- 2 x^{2} - 14 x + 5 = 0

x = - \frac{7 + 59}{2}, x = \frac{59 - 7}{2}

Decimal Notation

x = - 7.34057 \dots, x = 0.34057 \dots

Solution steps

- 2 x^{2} - 14 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 ( - 2 ) \cdot 5}{2 ( - 2 )}

(- 14)^{2} - 4 (- 2) \cdot 5 = 259

x_{1, 2} = \frac{- ( - 14 ) \pm 2 59}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 59}{2 ( - 2 )}, x_{2} = \frac{- ( - 14 ) - 2 59}{2 ( - 2 )}

x = \frac{- ( - 14 ) + 2 59}{2 ( - 2 )} : - \frac{7 + 59}{2}

x = \frac{- ( - 14 ) - 2 59}{2 ( - 2 )} : \frac{59 - 7}{2}

The solutions to the quadratic equation are:

x = - \frac{7 + 59}{2}, x = \frac{59 - 7}{2}

3 (1 - 4 x) - \frac{( 2 x - 1 ) ^{2}}{2} = 7

x^{2} + 10 x - 19 = 0

(4 x + 3) - (5 x + 2) (2 x - 5) = 0

- 5 x^{2} - 400 = - 90 x

2 (x^{2} + 2) = - 9 x

What are the solutions to the equation -2x^2-14x+5=0 ?
The solutions to the equation -2x^2-14x+5=0 are x=-(7+sqrt(59))/2 ,x=(sqrt(59)-7)/2
Find the zeros of -2x^2-14x+5=0
The zeros of -2x^2-14x+5=0 are x=-(7+sqrt(59))/2 ,x=(sqrt(59)-7)/2