What are the solutions to the equation 16x^2-4=4x^2+3/4 ?

The solutions to the equation 16x^2-4=4x^2+3/4 are x=(sqrt(19))/(4sqrt(3)),x=-(sqrt(19))/(4sqrt(3))

Find the zeros of 16x^2-4=4x^2+3/4

The zeros of 16x^2-4=4x^2+3/4 are x=(sqrt(19))/(4sqrt(3)),x=-(sqrt(19))/(4sqrt(3))

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16 x^{2} - 4 = 4 x^{2} + \frac{3}{4}

x = \frac{19}{4 3}, x = - \frac{19}{4 3}

Decimal Notation

x = 0.62915 \dots, x = - 0.62915 \dots

Solution steps

16 x^{2} - 4 = 4 x^{2} + \frac{3}{4}

Move

4

to the right side

16 x^{2} = 4 x^{2} + \frac{3}{4} + 4

Move

4 x^{2}

to the left side

12 x^{2} = \frac{3}{4} + 4

Simplify

\frac{3}{4} + 4 : \frac{19}{4}

12 x^{2} = \frac{19}{4}

Divide both sides by

12

x^{2} = \frac{19}{48}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{19}{48}, x = - \frac{19}{48}

\frac{19}{48} = \frac{19}{4 3}

- \frac{19}{48} = - \frac{19}{4 3}

x = \frac{19}{4 3}, x = - \frac{19}{4 3}

2 x^{2} - 8 x + 13

x^{2} - 6 x = - 10 x + 12

2 (x - 3)^{2} - 72 = 0

3 k^{2} - 14 k - 21 = 0

x, x^{2} + 2 k x - 3 = k x^{2} + 1.4

What are the solutions to the equation 16x^2-4=4x^2+3/4 ?
The solutions to the equation 16x^2-4=4x^2+3/4 are x=(sqrt(19))/(4sqrt(3)),x=-(sqrt(19))/(4sqrt(3))
Find the zeros of 16x^2-4=4x^2+3/4
The zeros of 16x^2-4=4x^2+3/4 are x=(sqrt(19))/(4sqrt(3)),x=-(sqrt(19))/(4sqrt(3))