What are the solutions to the equation 25-4x^2=0 ?

The solutions to the equation 25-4x^2=0 are x= 5/2 ,x=-5/2

Find the zeros of 25-4x^2=0

The zeros of 25-4x^2=0 are x= 5/2 ,x=-5/2

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25 - 4 x^{2} = 0

x = \frac{5}{2}, x = - \frac{5}{2}

Decimal Notation

x = 2.5, x = - 2.5

Solution steps

25 - 4 x^{2} = 0

Move

25

to the right side

- 4 x^{2} = - 25

Divide both sides by

- 4

x^{2} = \frac{25}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{25}{4}, x = - \frac{25}{4}

\frac{25}{4} = \frac{5}{2}

- \frac{25}{4} = - \frac{5}{2}

x = \frac{5}{2}, x = - \frac{5}{2}

12 x^{2} + 18 x = (12 x + 18)

(x - 2)^{2} - 6 = 0

- x^{2} - 3 x + 10

3 x^{2} - 14 x - 21 = 0

- 3 x^{2} - 18 x - 26

What are the solutions to the equation 25-4x^2=0 ?
The solutions to the equation 25-4x^2=0 are x= 5/2 ,x=-5/2
Find the zeros of 25-4x^2=0
The zeros of 25-4x^2=0 are x= 5/2 ,x=-5/2