What are the solutions to the equation x^2-200x+4000=0 ?

The solutions to the equation x^2-200x+4000=0 are x=20(5+sqrt(15)),x=20(5-sqrt(15))

Find the zeros of x^2-200x+4000=0

The zeros of x^2-200x+4000=0 are x=20(5+sqrt(15)),x=20(5-sqrt(15))

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x^{2} - 200 x + 4000 = 0

x = 20 (5 + 15), x = 20 (5 - 15)

Decimal Notation

x = 177.45966 \dots, x = 22.54033 \dots

Solution steps

x^{2} - 200 x + 4000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 200 ) \pm ( - 200 ) ^{2} - 4 \cdot 1 \cdot 4000}{2 \cdot 1}

(- 200)^{2} - 4 \cdot 1 \cdot 4000 = 4015

x_{1, 2} = \frac{- ( - 200 ) \pm 40 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 200 ) + 40 15}{2 \cdot 1}, x_{2} = \frac{- ( - 200 ) - 40 15}{2 \cdot 1}

x = \frac{- ( - 200 ) + 40 15}{2 \cdot 1} : 20 (5 + 15)

x = \frac{- ( - 200 ) - 40 15}{2 \cdot 1} : 20 (5 - 15)

The solutions to the quadratic equation are:

x = 20 (5 + 15), x = 20 (5 - 15)

(x + 1)^{2} + (x + 2)^{2} = x^{2} + 6

28 r^{2} - 49 r = 21 r

(m - 2) x^{2} + (2 m + 1) x = m^{2} + 5 m + 1

x^{2} + 9 x - 136 = 0

4 d^{2} + 9 d - 2 = 4 d

What are the solutions to the equation x^2-200x+4000=0 ?
The solutions to the equation x^2-200x+4000=0 are x=20(5+sqrt(15)),x=20(5-sqrt(15))
Find the zeros of x^2-200x+4000=0
The zeros of x^2-200x+4000=0 are x=20(5+sqrt(15)),x=20(5-sqrt(15))