What are the solutions to the equation 28r^2-49r=21r ?

The solutions to the equation 28r^2-49r=21r are r= 5/2 ,r=0

Find the zeros of 28r^2-49r=21r

The zeros of 28r^2-49r=21r are r= 5/2 ,r=0

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28 r^{2} - 49 r = 21 r

r = \frac{5}{2}, r = 0

Decimal Notation

r = 2.5, r = 0

Solution steps

28 r^{2} - 49 r = 21 r

Move

21 r

to the left side

28 r^{2} - 70 r = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 70 ) \pm ( - 70 ) ^{2} - 4 \cdot 28 \cdot 0}{2 \cdot 28}

(- 70)^{2} - 4 \cdot 28 \cdot 0 = 70

r_{1, 2} = \frac{- ( - 70 ) \pm 70}{2 \cdot 28}

Separate the solutions

r_{1} = \frac{- ( - 70 ) + 70}{2 \cdot 28}, r_{2} = \frac{- ( - 70 ) - 70}{2 \cdot 28}

r = \frac{- ( - 70 ) + 70}{2 \cdot 28} : \frac{5}{2}

r = \frac{- ( - 70 ) - 70}{2 \cdot 28} : 0

The solutions to the quadratic equation are:

r = \frac{5}{2}, r = 0

(m - 2) x^{2} + (2 m + 1) x = m^{2} + 5 m + 1

x^{2} + 9 x - 136 = 0

4 d^{2} + 9 d - 2 = 4 d

9 x^{2} - 169 = 0

144 = x^{2} + 10 x

What are the solutions to the equation 28r^2-49r=21r ?
The solutions to the equation 28r^2-49r=21r are r= 5/2 ,r=0
Find the zeros of 28r^2-49r=21r
The zeros of 28r^2-49r=21r are r= 5/2 ,r=0