What are the solutions to the equation 144=x^2+10x ?

The solutions to the equation 144=x^2+10x are x=8,x=-18

Find the zeros of 144=x^2+10x

The zeros of 144=x^2+10x are x=8,x=-18

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144 = x^{2} + 10 x

x = 8, x = - 18

Solution steps

144 = x^{2} + 10 x

Switch sides

x^{2} + 10 x = 144

Move

144

to the left side

x^{2} + 10 x - 144 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 144 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 144) = 26

x_{1, 2} = \frac{- 10 \pm 26}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 26}{2 \cdot 1}, x_{2} = \frac{- 10 - 26}{2 \cdot 1}

x = \frac{- 10 + 26}{2 \cdot 1} : 8

x = \frac{- 10 - 26}{2 \cdot 1} : - 18

The solutions to the quadratic equation are:

x = 8, x = - 18

3 x^{2} - 18 x + 15

- 3 (2 x - 1) (2 x + 1) = 2

6 - 7 x^{2} = 7

x^{2} - x = \frac{( x + 1 ) ( x + 3 )}{2} - 2

n^{2} + 5 n + 7 = 7

What are the solutions to the equation 144=x^2+10x ?
The solutions to the equation 144=x^2+10x are x=8,x=-18
Find the zeros of 144=x^2+10x
The zeros of 144=x^2+10x are x=8,x=-18