What are the solutions to the equation n^2+5n+7=7 ?

The solutions to the equation n^2+5n+7=7 are n=0,n=-5

Find the zeros of n^2+5n+7=7

The zeros of n^2+5n+7=7 are n=0,n=-5

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n^{2} + 5 n + 7 = 7

n = 0, n = - 5

Solution steps

n^{2} + 5 n + 7 = 7

Move

7

to the left side

n^{2} + 5 n = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 0 = 5

n_{1, 2} = \frac{- 5 \pm 5}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 5 + 5}{2 \cdot 1}, n_{2} = \frac{- 5 - 5}{2 \cdot 1}

n = \frac{- 5 + 5}{2 \cdot 1} : 0

n = \frac{- 5 - 5}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

n = 0, n = - 5

x, 5 x^{2} + 2 y^{2} = 0

x, f (a + b) = x^{2} - 4 x

b^{2} - \frac{4}{9} = 0

9 w^{2} - 31 w - 20 = 0

2 (w^{2} - 2 w) = 5

What are the solutions to the equation n^2+5n+7=7 ?
The solutions to the equation n^2+5n+7=7 are n=0,n=-5
Find the zeros of n^2+5n+7=7
The zeros of n^2+5n+7=7 are n=0,n=-5