What are the solutions to the equation x^2+80x+1600=0 ?

The solutions to the equation x^2+80x+1600=0 are x=-40

Find the zeros of x^2+80x+1600=0

The zeros of x^2+80x+1600=0 are x=-40

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x^{2} + 80 x + 1600 = 0

x = - 40

Solution steps

x^{2} + 80 x + 1600 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 80 \pm 8 0 ^{2} - 4 \cdot 1 \cdot 1600}{2 \cdot 1}

8 0^{2} - 4 \cdot 1 \cdot 1600 = 0

x_{1, 2} = \frac{- 80 \pm 0}{2 \cdot 1}

x = \frac{- 80}{2 \cdot 1}

\frac{- 80}{2 \cdot 1} = - 40

x = - 40

The solution to the quadratic equation is:

x = - 40

4.9 x^{2} - 205.06 x - 210 = 0

(3 x - 1)^{2} = 75

x (x - 3) = - 1

x, x^{2} + y^{2} = r

3 x^{2} - 6 x = x^{2}

What are the solutions to the equation x^2+80x+1600=0 ?
The solutions to the equation x^2+80x+1600=0 are x=-40
Find the zeros of x^2+80x+1600=0
The zeros of x^2+80x+1600=0 are x=-40