What are the solutions to the equation solvefor x,x^2+y^2=r ?

The solutions to the equation solvefor x,x^2+y^2=r are x=sqrt(r-y^2),x=-sqrt(r-y^2)

Find the zeros of solvefor x,x^2+y^2=r

The zeros of solvefor x,x^2+y^2=r are x=sqrt(r-y^2),x=-sqrt(r-y^2)

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solve for

x, x^{2} + y^{2} = r

x = r - y^{2}, x = - r - y^{2}

Solution steps

x^{2} + y^{2} = r

Move

y^{2}

to the right side

x^{2} = r - y^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = r - y^{2}, x = - r - y^{2}

3 x^{2} - 6 x = x^{2}

x, 2 x^{2} - x y - y^{2} = 44

(x + 8)^{2} = 169

9 x^{2} = - 6 x + 1

18 x^{2} - 25 = - 8 x^{2} - (- 16)

What are the solutions to the equation solvefor x,x^2+y^2=r ?
The solutions to the equation solvefor x,x^2+y^2=r are x=sqrt(r-y^2),x=-sqrt(r-y^2)
Find the zeros of solvefor x,x^2+y^2=r
The zeros of solvefor x,x^2+y^2=r are x=sqrt(r-y^2),x=-sqrt(r-y^2)