What are the solutions to the equation 4v^2-19v-5=0 ?

The solutions to the equation 4v^2-19v-5=0 are v=5,v=-1/4

Find the zeros of 4v^2-19v-5=0

The zeros of 4v^2-19v-5=0 are v=5,v=-1/4

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4 v^{2} - 19 v - 5 = 0

v = 5, v = - \frac{1}{4}

Decimal Notation

v = 5, v = - 0.25

Solution steps

4 v^{2} - 19 v - 5 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 4 ( - 5 )}{2 \cdot 4}

(- 19)^{2} - 4 \cdot 4 (- 5) = 21

v_{1, 2} = \frac{- ( - 19 ) \pm 21}{2 \cdot 4}

Separate the solutions

v_{1} = \frac{- ( - 19 ) + 21}{2 \cdot 4}, v_{2} = \frac{- ( - 19 ) - 21}{2 \cdot 4}

v = \frac{- ( - 19 ) + 21}{2 \cdot 4} : 5

v = \frac{- ( - 19 ) - 21}{2 \cdot 4} : - \frac{1}{4}

The solutions to the quadratic equation are:

v = 5, v = - \frac{1}{4}

x^{2} + 100 x - 7500 = 0

5 = 10 t + \frac{1}{2} (- 9.8) t^{2}

25 x - 19 = 3 (x^{2} + 3)

x^{2} + x - 12 = 0

(2 x - 5)^{2} = 169

What are the solutions to the equation 4v^2-19v-5=0 ?
The solutions to the equation 4v^2-19v-5=0 are v=5,v=-1/4
Find the zeros of 4v^2-19v-5=0
The zeros of 4v^2-19v-5=0 are v=5,v=-1/4