What are the solutions to the equation 20x^2-7x=14 ?

The solutions to the equation 20x^2-7x=14 are x=(7+sqrt(1169))/(40),x=(7-sqrt(1169))/(40)

Find the zeros of 20x^2-7x=14

The zeros of 20x^2-7x=14 are x=(7+sqrt(1169))/(40),x=(7-sqrt(1169))/(40)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

20 x^{2} - 7 x = 14

x = \frac{7 + 1169}{40}, x = \frac{7 - 1169}{40}

Decimal Notation

x = 1.02976 \dots, x = - 0.67976 \dots

Solution steps

20 x^{2} - 7 x = 14

Move

14

to the left side

20 x^{2} - 7 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 20 ( - 14 )}{2 \cdot 20}

(- 7)^{2} - 4 \cdot 20 (- 14) = 1169

x_{1, 2} = \frac{- ( - 7 ) \pm 1169}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 1169}{2 \cdot 20}, x_{2} = \frac{- ( - 7 ) - 1169}{2 \cdot 20}

x = \frac{- ( - 7 ) + 1169}{2 \cdot 20} : \frac{7 + 1169}{40}

x = \frac{- ( - 7 ) - 1169}{2 \cdot 20} : \frac{7 - 1169}{40}

The solutions to the quadratic equation are:

x = \frac{7 + 1169}{40}, x = \frac{7 - 1169}{40}

x^{2} - 8 x - 3 = 6

x, x^{2} + x y + y^{2} = 16

3 x^{2} + x - \frac{1}{12} = 0

11 x^{2} - 98 = - 11 + 9 x

q^{2} + 2 q - 15 = - 3 q

What are the solutions to the equation 20x^2-7x=14 ?
The solutions to the equation 20x^2-7x=14 are x=(7+sqrt(1169))/(40),x=(7-sqrt(1169))/(40)
Find the zeros of 20x^2-7x=14
The zeros of 20x^2-7x=14 are x=(7+sqrt(1169))/(40),x=(7-sqrt(1169))/(40)