What are the solutions to the equation 4m^2+2m=3 ?

The solutions to the equation 4m^2+2m=3 are m=(-1+sqrt(13))/4 ,m=-(1+sqrt(13))/4

Find the zeros of 4m^2+2m=3

The zeros of 4m^2+2m=3 are m=(-1+sqrt(13))/4 ,m=-(1+sqrt(13))/4

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4 m^{2} + 2 m = 3

m = \frac{- 1 + 13}{4}, m = - \frac{1 + 13}{4}

Solution steps

4 m^{2} + 2 m = 3

Move

3

to the left side

4 m^{2} + 2 m - 3 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

2^{2} - 4 \cdot 4 (- 3) = 213

m_{1, 2} = \frac{- 2 \pm 2 13}{2 \cdot 4}

Separate the solutions

m_{1} = \frac{- 2 + 2 13}{2 \cdot 4}, m_{2} = \frac{- 2 - 2 13}{2 \cdot 4}

m = \frac{- 2 + 2 13}{2 \cdot 4} : \frac{- 1 + 13}{4}

m = \frac{- 2 - 2 13}{2 \cdot 4} : - \frac{1 + 13}{4}

The solutions to the quadratic equation are:

m = \frac{- 1 + 13}{4}, m = - \frac{1 + 13}{4}

x^{4} + 20 x^{2} - 125

x^{2} + x - 110 = 0

x^{2} + 55 = - 14 x + 10

0.3 (n - 5) = 0.4 - 0.2 n

2 x^{2} + 6 x - 20

What are the solutions to the equation 4m^2+2m=3 ?
The solutions to the equation 4m^2+2m=3 are m=(-1+sqrt(13))/4 ,m=-(1+sqrt(13))/4
Find the zeros of 4m^2+2m=3
The zeros of 4m^2+2m=3 are m=(-1+sqrt(13))/4 ,m=-(1+sqrt(13))/4