What are the solutions to the equation 4p^2+19p+12=-5 ?

The solutions to the equation 4p^2+19p+12=-5 are p=(-19+sqrt(89))/8 ,p=(-19-sqrt(89))/8

Find the zeros of 4p^2+19p+12=-5

The zeros of 4p^2+19p+12=-5 are p=(-19+sqrt(89))/8 ,p=(-19-sqrt(89))/8

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4 p^{2} + 19 p + 12 = - 5

p = \frac{- 19 + 89}{8}, p = \frac{- 19 - 89}{8}

Decimal Notation

p = - 1.19575 \dots, p = - 3.55424 \dots

Solution steps

4 p^{2} + 19 p + 12 = - 5

Move

5

to the left side

4 p^{2} + 19 p + 17 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 \cdot 4 \cdot 17}{2 \cdot 4}

1 9^{2} - 4 \cdot 4 \cdot 17 = 89

p_{1, 2} = \frac{- 19 \pm 89}{2 \cdot 4}

Separate the solutions

p_{1} = \frac{- 19 + 89}{2 \cdot 4}, p_{2} = \frac{- 19 - 89}{2 \cdot 4}

p = \frac{- 19 + 89}{2 \cdot 4} : \frac{- 19 + 89}{8}

p = \frac{- 19 - 89}{2 \cdot 4} : \frac{- 19 - 89}{8}

The solutions to the quadratic equation are:

p = \frac{- 19 + 89}{8}, p = \frac{- 19 - 89}{8}

8 y^{2} - 24 y = 0

x, f (x + 2) = x^{2} - 2 x + 5

y, x = y^{2} + 2 y - 1

x^{2} - 2 x + 6 = 2 x + 11

x^{2} = 8 x - 15

What are the solutions to the equation 4p^2+19p+12=-5 ?
The solutions to the equation 4p^2+19p+12=-5 are p=(-19+sqrt(89))/8 ,p=(-19-sqrt(89))/8
Find the zeros of 4p^2+19p+12=-5
The zeros of 4p^2+19p+12=-5 are p=(-19+sqrt(89))/8 ,p=(-19-sqrt(89))/8