What are the solutions to the equation t^2-6t+13=0 ?

The solutions to the equation t^2-6t+13=0 are t=3+2i,t=3-2i

Find the zeros of t^2-6t+13=0

The zeros of t^2-6t+13=0 are t=3+2i,t=3-2i

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t^{2} - 6 t + 13 = 0

t = 3 + 2 i, t = 3 - 2 i

Solution steps

t^{2} - 6 t + 13 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 13 : 4 i

t_{1, 2} = \frac{- ( - 6 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 6 ) + 4 i}{2 \cdot 1}, t_{2} = \frac{- ( - 6 ) - 4 i}{2 \cdot 1}

t = \frac{- ( - 6 ) + 4 i}{2 \cdot 1} : 3 + 2 i

t = \frac{- ( - 6 ) - 4 i}{2 \cdot 1} : 3 - 2 i

The solutions to the quadratic equation are:

t = 3 + 2 i, t = 3 - 2 i

2 m^{2} + 7 m - 4 = 0

y^{2} + 3 y - 1

(x - 1)^{2} - x (2 x - 5) = 0

x^{2} - 15 x - 16 = - 9 x - 9

36 x^{2} + 4 = 40

What are the solutions to the equation t^2-6t+13=0 ?
The solutions to the equation t^2-6t+13=0 are t=3+2i,t=3-2i
Find the zeros of t^2-6t+13=0
The zeros of t^2-6t+13=0 are t=3+2i,t=3-2i