What are the solutions to the equation 21x^2-16x-50=0 ?

The solutions to the equation 21x^2-16x-50=0 are x=(8+sqrt(1114))/(21),x=(8-sqrt(1114))/(21)

Find the zeros of 21x^2-16x-50=0

The zeros of 21x^2-16x-50=0 are x=(8+sqrt(1114))/(21),x=(8-sqrt(1114))/(21)

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21 x^{2} - 16 x - 50 = 0

x = \frac{8 + 1114}{21}, x = \frac{8 - 1114}{21}

Decimal Notation

x = 1.97031 \dots, x = - 1.20841 \dots

Solution steps

21 x^{2} - 16 x - 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 21 ( - 50 )}{2 \cdot 21}

(- 16)^{2} - 4 \cdot 21 (- 50) = 21114

x_{1, 2} = \frac{- ( - 16 ) \pm 2 1114}{2 \cdot 21}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2 1114}{2 \cdot 21}, x_{2} = \frac{- ( - 16 ) - 2 1114}{2 \cdot 21}

x = \frac{- ( - 16 ) + 2 1114}{2 \cdot 21} : \frac{8 + 1114}{21}

x = \frac{- ( - 16 ) - 2 1114}{2 \cdot 21} : \frac{8 - 1114}{21}

The solutions to the quadratic equation are:

x = \frac{8 + 1114}{21}, x = \frac{8 - 1114}{21}

64 b^{2} + 48 b + 9 = 0

x^{2} + x + 11 = 5 x - 8

2 v^{2} + 4 v + 12 = 0

r, A = 3 r^{2}

4 - 6 x = x^{2}

What are the solutions to the equation 21x^2-16x-50=0 ?
The solutions to the equation 21x^2-16x-50=0 are x=(8+sqrt(1114))/(21),x=(8-sqrt(1114))/(21)
Find the zeros of 21x^2-16x-50=0
The zeros of 21x^2-16x-50=0 are x=(8+sqrt(1114))/(21),x=(8-sqrt(1114))/(21)