What are the solutions to the equation x^2+x+11=5x-8 ?

The solutions to the equation x^2+x+11=5x-8 are x=2+sqrt(15)i,x=2-sqrt(15)i

Find the zeros of x^2+x+11=5x-8

The zeros of x^2+x+11=5x-8 are x=2+sqrt(15)i,x=2-sqrt(15)i

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x^{2} + x + 11 = 5 x - 8

x = 2 + 15 i, x = 2 - 15 i

Solution steps

x^{2} + x + 11 = 5 x - 8

Move

8

to the left side

x^{2} + x + 19 = 5 x

Move

5 x

to the left side

x^{2} - 4 x + 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 19}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 19 : 215 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 15 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 15 i}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 15 i}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 15 i}{2 \cdot 1} : 2 + 15 i

x = \frac{- ( - 4 ) - 2 15 i}{2 \cdot 1} : 2 - 15 i

The solutions to the quadratic equation are:

x = 2 + 15 i, x = 2 - 15 i

2 v^{2} + 4 v + 12 = 0

r, A = 3 r^{2}

4 - 6 x = x^{2}

5 t^{2} + 8 t - 30 = 0

3 (x^{2} - 2) = 66

What are the solutions to the equation x^2+x+11=5x-8 ?
The solutions to the equation x^2+x+11=5x-8 are x=2+sqrt(15)i,x=2-sqrt(15)i
Find the zeros of x^2+x+11=5x-8
The zeros of x^2+x+11=5x-8 are x=2+sqrt(15)i,x=2-sqrt(15)i