What are the solutions to the equation 5t^2+8t-30=0 ?

The solutions to the equation 5t^2+8t-30=0 are t=(-4+sqrt(166))/5 ,t=-(4+sqrt(166))/5

Find the zeros of 5t^2+8t-30=0

The zeros of 5t^2+8t-30=0 are t=(-4+sqrt(166))/5 ,t=-(4+sqrt(166))/5

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5 t^{2} + 8 t - 30 = 0

t = \frac{- 4 + 166}{5}, t = - \frac{4 + 166}{5}

Decimal Notation

t = 1.77681 \dots, t = - 3.37681 \dots

Solution steps

5 t^{2} + 8 t - 30 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 5 ( - 30 )}{2 \cdot 5}

8^{2} - 4 \cdot 5 (- 30) = 2166

t_{1, 2} = \frac{- 8 \pm 2 166}{2 \cdot 5}

Separate the solutions

t_{1} = \frac{- 8 + 2 166}{2 \cdot 5}, t_{2} = \frac{- 8 - 2 166}{2 \cdot 5}

t = \frac{- 8 + 2 166}{2 \cdot 5} : \frac{- 4 + 166}{5}

t = \frac{- 8 - 2 166}{2 \cdot 5} : - \frac{4 + 166}{5}

The solutions to the quadratic equation are:

t = \frac{- 4 + 166}{5}, t = - \frac{4 + 166}{5}

3 (x^{2} - 2) = 66

4 (2 x + 3)^{2} = 64

2 x^{2} - 15 x + 2 = - 10 x

x^{2} + 4 x + 49 = 0

x, x^{2} + y^{2} = - 25

What are the solutions to the equation 5t^2+8t-30=0 ?
The solutions to the equation 5t^2+8t-30=0 are t=(-4+sqrt(166))/5 ,t=-(4+sqrt(166))/5
Find the zeros of 5t^2+8t-30=0
The zeros of 5t^2+8t-30=0 are t=(-4+sqrt(166))/5 ,t=-(4+sqrt(166))/5