What are the solutions to the equation 4(2x+3)^2=64 ?

The solutions to the equation 4(2x+3)^2=64 are x= 1/2 ,x=-7/2

Find the zeros of 4(2x+3)^2=64

The zeros of 4(2x+3)^2=64 are x= 1/2 ,x=-7/2

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4 (2 x + 3)^{2} = 64

x = \frac{1}{2}, x = - \frac{7}{2}

Decimal Notation

x = 0.5, x = - 3.5

Solution steps

4 (2 x + 3)^{2} = 64

Divide both sides by

4

(2 x + 3)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 3 = 16 : x = \frac{1}{2}

Solve

2 x + 3 = - 16 : x = - \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{7}{2}

2 x^{2} - 15 x + 2 = - 10 x

x^{2} + 4 x + 49 = 0

x, x^{2} + y^{2} = - 25

(2 x - 1)^{(2)} - 5 (2 x - 1) - 6 = 0

- 6 = (2 x - 4)^{2} - 10

What are the solutions to the equation 4(2x+3)^2=64 ?
The solutions to the equation 4(2x+3)^2=64 are x= 1/2 ,x=-7/2
Find the zeros of 4(2x+3)^2=64
The zeros of 4(2x+3)^2=64 are x= 1/2 ,x=-7/2