What are the solutions to the equation -6=(2x-4)^2-10 ?

The solutions to the equation -6=(2x-4)^2-10 are x=3,x=1

Find the zeros of -6=(2x-4)^2-10

The zeros of -6=(2x-4)^2-10 are x=3,x=1

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- 6 = (2 x - 4)^{2} - 10

x = 3, x = 1

Solution steps

- 6 = (2 x - 4)^{2} - 10

Switch sides

(2 x - 4)^{2} - 10 = - 6

Move

10

to the right side

(2 x - 4)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 4 = 4 : x = 3

Solve

2 x - 4 = - 4 : x = 1

The solutions to the quadratic equation are:

x = 3, x = 1

(7 x + 4)^{2} = 48

3 x^{2} + 5 x = 7 (x^{2} + x)

5 x^{2} + 40 x - 410 = 0

y, y^{2} - y - x^{2} = 0

2 (x - 1)^{2} - (x + 4) (x - 4) = 19 - x

What are the solutions to the equation -6=(2x-4)^2-10 ?
The solutions to the equation -6=(2x-4)^2-10 are x=3,x=1
Find the zeros of -6=(2x-4)^2-10
The zeros of -6=(2x-4)^2-10 are x=3,x=1