What are the solutions to the equation 4x^2+17x+17=1 ?

The solutions to the equation 4x^2+17x+17=1 are x=(-17+sqrt(33))/8 ,x=(-17-sqrt(33))/8

Find the zeros of 4x^2+17x+17=1

The zeros of 4x^2+17x+17=1 are x=(-17+sqrt(33))/8 ,x=(-17-sqrt(33))/8

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4 x^{2} + 17 x + 17 = 1

x = \frac{- 17 + 33}{8}, x = \frac{- 17 - 33}{8}

Decimal Notation

x = - 1.40692 \dots, x = - 2.84307 \dots

Solution steps

4 x^{2} + 17 x + 17 = 1

Move

1

to the left side

4 x^{2} + 17 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 4 \cdot 16}{2 \cdot 4}

1 7^{2} - 4 \cdot 4 \cdot 16 = 33

x_{1, 2} = \frac{- 17 \pm 33}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 17 + 33}{2 \cdot 4}, x_{2} = \frac{- 17 - 33}{2 \cdot 4}

x = \frac{- 17 + 33}{2 \cdot 4} : \frac{- 17 + 33}{8}

x = \frac{- 17 - 33}{2 \cdot 4} : \frac{- 17 - 33}{8}

The solutions to the quadratic equation are:

x = \frac{- 17 + 33}{8}, x = \frac{- 17 - 33}{8}

mn x^{2} = mn - (m^{2} - n^{2}) x

x^{2} + 3 x - 0.9 = 0

4.905 x^{2} - 90 x - 150 = 0

x^{2} - 10 x + 25 = 0

a, 2 - j^{4} = (a + 3 jb)^{2}

What are the solutions to the equation 4x^2+17x+17=1 ?
The solutions to the equation 4x^2+17x+17=1 are x=(-17+sqrt(33))/8 ,x=(-17-sqrt(33))/8
Find the zeros of 4x^2+17x+17=1
The zeros of 4x^2+17x+17=1 are x=(-17+sqrt(33))/8 ,x=(-17-sqrt(33))/8