What are the solutions to the equation x^2+3x-0.9=0 ?

The solutions to the equation x^2+3x-0.9=0 are x=(3(sqrt(35)-5))/(10),x=-(3(5+sqrt(35)))/(10)

Find the zeros of x^2+3x-0.9=0

The zeros of x^2+3x-0.9=0 are x=(3(sqrt(35)-5))/(10),x=-(3(5+sqrt(35)))/(10)

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x^{2} + 3 x - 0.9 = 0

x = \frac{3 ( 35 - 5 )}{10}, x = - \frac{3 ( 5 + 35 )}{10}

Decimal Notation

x = 0.27482 \dots, x = - 3.27482 \dots

Solution steps

x^{2} + 3 x - 0.9 = 0

Multiply both sides by

10

10 x^{2} + 30 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 30 \pm 3 0 ^{2} - 4 \cdot 10 ( - 9 )}{2 \cdot 10}

3 0^{2} - 4 \cdot 10 (- 9) = 635

x_{1, 2} = \frac{- 30 \pm 6 35}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 30 + 6 35}{2 \cdot 10}, x_{2} = \frac{- 30 - 6 35}{2 \cdot 10}

x = \frac{- 30 + 6 35}{2 \cdot 10} : \frac{3 ( 35 - 5 )}{10}

x = \frac{- 30 - 6 35}{2 \cdot 10} : - \frac{3 ( 5 + 35 )}{10}

The solutions to the quadratic equation are:

x = \frac{3 ( 35 - 5 )}{10}, x = - \frac{3 ( 5 + 35 )}{10}

4.905 x^{2} - 90 x - 150 = 0

x^{2} - 10 x + 25 = 0

a, 2 - j^{4} = (a + 3 jb)^{2}

7 x^{2} + 18 x = 10 x^{2} + 12 x

- 25 x^{2} - 30 x - 9 = 0

What are the solutions to the equation x^2+3x-0.9=0 ?
The solutions to the equation x^2+3x-0.9=0 are x=(3(sqrt(35)-5))/(10),x=-(3(5+sqrt(35)))/(10)
Find the zeros of x^2+3x-0.9=0
The zeros of x^2+3x-0.9=0 are x=(3(sqrt(35)-5))/(10),x=-(3(5+sqrt(35)))/(10)