What are the solutions to the equation -3b^2+b-A=0 ?

The solutions to the equation -3b^2+b-A=0 are b=-(-1+sqrt(1-12A))/6 ,b=-(-1-sqrt(1-12A))/6

Find the zeros of -3b^2+b-A=0

The zeros of -3b^2+b-A=0 are b=-(-1+sqrt(1-12A))/6 ,b=-(-1-sqrt(1-12A))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 3 b^{2} + b - A = 0

b = - \frac{- 1 + 1 - 12 A}{6}, b = - \frac{- 1 - 1 - 12 A}{6}

Solution steps

- 3 b^{2} + b - A = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 3 ) ( - A )}{2 ( - 3 )}

Simplify

1^{2} - 4 (- 3) (- A) : 1 - 12 A

b_{1, 2} = \frac{- 1 \pm 1 - 12 A}{2 ( - 3 )}

Separate the solutions

b_{1} = \frac{- 1 + 1 - 12 A}{2 ( - 3 )}, b_{2} = \frac{- 1 - 1 - 12 A}{2 ( - 3 )}

b = \frac{- 1 + 1 - 12 A}{2 ( - 3 )} : - \frac{- 1 + 1 - 12 A}{6}

b = \frac{- 1 - 1 - 12 A}{2 ( - 3 )} : - \frac{- 1 - 1 - 12 A}{6}

The solutions to the quadratic equation are:

b = - \frac{- 1 + 1 - 12 A}{6}, b = - \frac{- 1 - 1 - 12 A}{6}

4 x^{2} - 6 x + 5 = x + 1

2 x^{2} + 18 = 90

x^{2} + 3 x - 21 = 0

2 x^{2} + 5 x - 63 = 0

x^{2} - 4 x - 21 = - 12

What are the solutions to the equation -3b^2+b-A=0 ?
The solutions to the equation -3b^2+b-A=0 are b=-(-1+sqrt(1-12A))/6 ,b=-(-1-sqrt(1-12A))/6
Find the zeros of -3b^2+b-A=0
The zeros of -3b^2+b-A=0 are b=-(-1+sqrt(1-12A))/6 ,b=-(-1-sqrt(1-12A))/6