What are the solutions to the equation x^2+35=12x ?

The solutions to the equation x^2+35=12x are x=7,x=5

Find the zeros of x^2+35=12x

The zeros of x^2+35=12x are x=7,x=5

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x^{2} + 35 = 12 x

x = 7, x = 5

Solution steps

x^{2} + 35 = 12 x

Move

12 x

to the left side

x^{2} + 35 - 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 12 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 35}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 35 = 2

x_{1, 2} = \frac{- ( - 12 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 2}{2 \cdot 1}

x = \frac{- ( - 12 ) + 2}{2 \cdot 1} : 7

x = \frac{- ( - 12 ) - 2}{2 \cdot 1} : 5

The solutions to the quadratic equation are:

x = 7, x = 5

x, \frac{2 x ^{2}}{3} = d g

2 (x - 1) (x + 3) = (x + 5) (x - 5)

x^{2} - x + 3 = 4 x^{2} - 5

- x^{2} + 3 x - 2

[f (a)]^{2} = 3 x^{2} - x + 2

What are the solutions to the equation x^2+35=12x ?
The solutions to the equation x^2+35=12x are x=7,x=5
Find the zeros of x^2+35=12x
The zeros of x^2+35=12x are x=7,x=5