What are the solutions to the equation solvefor x,(2x^2)/3 =dg ?

The solutions to the equation solvefor x,(2x^2)/3 =dg are x=sqrt((3dg)/2),x=-sqrt((3dg)/2)

Find the zeros of solvefor x,(2x^2)/3 =dg

The zeros of solvefor x,(2x^2)/3 =dg are x=sqrt((3dg)/2),x=-sqrt((3dg)/2)

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solve for

x, \frac{2 x ^{2}}{3} = d g

x = \frac{3 d g}{2}, x = - \frac{3 d g}{2}

Solution steps

\frac{2 x ^{2}}{3} = d g

Multiply both sides by

3

2 x^{2} = 3 d g

Divide both sides by

2

x^{2} = \frac{3 d g}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{3 d g}{2}, x = - \frac{3 d g}{2}

2 (x - 1) (x + 3) = (x + 5) (x - 5)

x^{2} - x + 3 = 4 x^{2} - 5

- x^{2} + 3 x - 2

[f (a)]^{2} = 3 x^{2} - x + 2

- 4 x^{2} + 9 x - 3 = 0

What are the solutions to the equation solvefor x,(2x^2)/3 =dg ?
The solutions to the equation solvefor x,(2x^2)/3 =dg are x=sqrt((3dg)/2),x=-sqrt((3dg)/2)
Find the zeros of solvefor x,(2x^2)/3 =dg
The zeros of solvefor x,(2x^2)/3 =dg are x=sqrt((3dg)/2),x=-sqrt((3dg)/2)