What are the solutions to the equation -4x^2+9x-3=0 ?

The solutions to the equation -4x^2+9x-3=0 are x=(9-sqrt(33))/8 ,x=(9+sqrt(33))/8

Find the zeros of -4x^2+9x-3=0

The zeros of -4x^2+9x-3=0 are x=(9-sqrt(33))/8 ,x=(9+sqrt(33))/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 4 x^{2} + 9 x - 3 = 0

x = \frac{9 - 33}{8}, x = \frac{9 + 33}{8}

Decimal Notation

x = 0.40692 \dots, x = 1.84307 \dots

Solution steps

- 4 x^{2} + 9 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 4 ) ( - 3 )}{2 ( - 4 )}

9^{2} - 4 (- 4) (- 3) = 33

x_{1, 2} = \frac{- 9 \pm 33}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 9 + 33}{2 ( - 4 )}, x_{2} = \frac{- 9 - 33}{2 ( - 4 )}

x = \frac{- 9 + 33}{2 ( - 4 )} : \frac{9 - 33}{8}

x = \frac{- 9 - 33}{2 ( - 4 )} : \frac{9 + 33}{8}

The solutions to the quadratic equation are:

x = \frac{9 - 33}{8}, x = \frac{9 + 33}{8}

- 0.5 x^{2} + 3.2 x + 22 = 24

x - 2 x^{2}

39 x^{2} = 91

2 x^{2} + 5 x - 7 = 0

y, y^{2} = x^{3} - 8 x

What are the solutions to the equation -4x^2+9x-3=0 ?
The solutions to the equation -4x^2+9x-3=0 are x=(9-sqrt(33))/8 ,x=(9+sqrt(33))/8
Find the zeros of -4x^2+9x-3=0
The zeros of -4x^2+9x-3=0 are x=(9-sqrt(33))/8 ,x=(9+sqrt(33))/8