What are the solutions to the equation (3x-1)^2+6=0 ?

The solutions to the equation (3x-1)^2+6=0 are x= 1/3+isqrt(2/3),x= 1/3-isqrt(2/3)

Find the zeros of (3x-1)^2+6=0

The zeros of (3x-1)^2+6=0 are x= 1/3+isqrt(2/3),x= 1/3-isqrt(2/3)

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(3 x - 1)^{2} + 6 = 0

x = \frac{1}{3} + i \frac{2}{3}, x = \frac{1}{3} - i \frac{2}{3}

Solution steps

(3 x - 1)^{2} + 6 = 0

Move

6

to the right side

(3 x - 1)^{2} = - 6

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 1 = - 6 : x = \frac{1}{3} + i \frac{2}{3}

Solve

3 x - 1 = - - 6 : x = \frac{1}{3} - i \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{1}{3} + i \frac{2}{3}, x = \frac{1}{3} - i \frac{2}{3}

x, 4 x^{2} + 9 y^{2} = 0

2 y (y - 3) - (y - 3) = 0

3 x^{2} - x = 24

3 q^{2} - 120 q + 950 = 0

2 (x + 1)^{2} = 40

What are the solutions to the equation (3x-1)^2+6=0 ?
The solutions to the equation (3x-1)^2+6=0 are x= 1/3+isqrt(2/3),x= 1/3-isqrt(2/3)
Find the zeros of (3x-1)^2+6=0
The zeros of (3x-1)^2+6=0 are x= 1/3+isqrt(2/3),x= 1/3-isqrt(2/3)