What are the solutions to the equation 3q^2-120q+950=0 ?

The solutions to the equation 3q^2-120q+950=0 are q=(5(12+sqrt(30)))/3 ,q=(5(12-sqrt(30)))/3

Find the zeros of 3q^2-120q+950=0

The zeros of 3q^2-120q+950=0 are q=(5(12+sqrt(30)))/3 ,q=(5(12-sqrt(30)))/3

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3 q^{2} - 120 q + 950 = 0

q = \frac{5 ( 12 + 30 )}{3}, q = \frac{5 ( 12 - 30 )}{3}

Decimal Notation

q = 29.12870 \dots, q = 10.87129 \dots

Solution steps

3 q^{2} - 120 q + 950 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 120 ) \pm ( - 120 ) ^{2} - 4 \cdot 3 \cdot 950}{2 \cdot 3}

(- 120)^{2} - 4 \cdot 3 \cdot 950 = 1030

q_{1, 2} = \frac{- ( - 120 ) \pm 10 30}{2 \cdot 3}

Separate the solutions

q_{1} = \frac{- ( - 120 ) + 10 30}{2 \cdot 3}, q_{2} = \frac{- ( - 120 ) - 10 30}{2 \cdot 3}

q = \frac{- ( - 120 ) + 10 30}{2 \cdot 3} : \frac{5 ( 12 + 30 )}{3}

q = \frac{- ( - 120 ) - 10 30}{2 \cdot 3} : \frac{5 ( 12 - 30 )}{3}

The solutions to the quadratic equation are:

q = \frac{5 ( 12 + 30 )}{3}, q = \frac{5 ( 12 - 30 )}{3}

2 (x + 1)^{2} = 40

x^{2} - 8 x - 56 = 0

x^{2} - 0.5 x - 3 = 0

4 x^{2} - 5 x = 21

24 x^{2} + 5 x - 1 = 0

What are the solutions to the equation 3q^2-120q+950=0 ?
The solutions to the equation 3q^2-120q+950=0 are q=(5(12+sqrt(30)))/3 ,q=(5(12-sqrt(30)))/3
Find the zeros of 3q^2-120q+950=0
The zeros of 3q^2-120q+950=0 are q=(5(12+sqrt(30)))/3 ,q=(5(12-sqrt(30)))/3