What are the solutions to the equation 4x^2-5x=21 ?

The solutions to the equation 4x^2-5x=21 are x=3,x=-7/4

Find the zeros of 4x^2-5x=21

The zeros of 4x^2-5x=21 are x=3,x=-7/4

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4 x^{2} - 5 x = 21

x = 3, x = - \frac{7}{4}

Decimal Notation

x = 3, x = - 1.75

Solution steps

4 x^{2} - 5 x = 21

Move

21

to the left side

4 x^{2} - 5 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 4 ( - 21 )}{2 \cdot 4}

(- 5)^{2} - 4 \cdot 4 (- 21) = 19

x_{1, 2} = \frac{- ( - 5 ) \pm 19}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 19}{2 \cdot 4}, x_{2} = \frac{- ( - 5 ) - 19}{2 \cdot 4}

x = \frac{- ( - 5 ) + 19}{2 \cdot 4} : 3

x = \frac{- ( - 5 ) - 19}{2 \cdot 4} : - \frac{7}{4}

The solutions to the quadratic equation are:

x = 3, x = - \frac{7}{4}

24 x^{2} + 5 x - 1 = 0

4 x^{2} - 8 = 4

a (x) = x^{2} + 7 x + 12

2 x^{2} + 48 = 0

6 + 3 x^{2} = - 3 x

What are the solutions to the equation 4x^2-5x=21 ?
The solutions to the equation 4x^2-5x=21 are x=3,x=-7/4
Find the zeros of 4x^2-5x=21
The zeros of 4x^2-5x=21 are x=3,x=-7/4