What are the solutions to the equation 2x^2+48=0 ?

The solutions to the equation 2x^2+48=0 are x=2sqrt(6)i,x=-2sqrt(6)i

Find the zeros of 2x^2+48=0

The zeros of 2x^2+48=0 are x=2sqrt(6)i,x=-2sqrt(6)i

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2 x^{2} + 48 = 0

x = 26 i, x = - 26 i

Solution steps

2 x^{2} + 48 = 0

Move

48

to the right side

2 x^{2} = - 48

Divide both sides by

2

x^{2} = - 24

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 24, x = - - 24

- 24 = 26 i

- - 24 = - 26 i

x = 26 i, x = - 26 i

6 + 3 x^{2} = - 3 x

x (x - 7) - 2 = 0

x, x^{2} z + 3 y^{2} - x y = 10

2 x^{2} - 8 x - 1 = 0

4 r^{2} - 19 r + 21 = 2

What are the solutions to the equation 2x^2+48=0 ?
The solutions to the equation 2x^2+48=0 are x=2sqrt(6)i,x=-2sqrt(6)i
Find the zeros of 2x^2+48=0
The zeros of 2x^2+48=0 are x=2sqrt(6)i,x=-2sqrt(6)i