What are the solutions to the equation -16t^2-16=0 ?

The solutions to the equation -16t^2-16=0 are t=i,t=-i

Find the zeros of -16t^2-16=0

The zeros of -16t^2-16=0 are t=i,t=-i

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- 16 t^{2} - 16 = 0

t = i, t = - i

Solution steps

- 16 t^{2} - 16 = 0

Move

16

to the right side

- 16 t^{2} = 16

Divide both sides by

- 16

t^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = - 1, t = - - 1

- 1 = i

- - 1 = - i

t = i, t = - i

x^{2} - 14 x + 54 = 0

10 m = 7 m^{2}

2 y^{2} - 5 y = 12

x^{2} + 13 x - 114 = 0

20.76672 = x^{2} \cdot 12.7

What are the solutions to the equation -16t^2-16=0 ?
The solutions to the equation -16t^2-16=0 are t=i,t=-i
Find the zeros of -16t^2-16=0
The zeros of -16t^2-16=0 are t=i,t=-i