What are the solutions to the equation 3/4 x^2-1/3 =5 ?

The solutions to the equation 3/4 x^2-1/3 =5 are x= 8/3 ,x=-8/3

Find the zeros of 3/4 x^2-1/3 =5

The zeros of 3/4 x^2-1/3 =5 are x= 8/3 ,x=-8/3

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\frac{3}{4} x^{2} - \frac{1}{3} = 5

x = \frac{8}{3}, x = - \frac{8}{3}

Decimal Notation

x = 2.66666 \dots, x = - 2.66666 \dots

Solution steps

\frac{3}{4} x^{2} - \frac{1}{3} = 5

Move

\frac{1}{3}

to the right side

\frac{3}{4} x^{2} = 5 + \frac{1}{3}

Simplify

5 + \frac{1}{3} : \frac{16}{3}

\frac{3}{4} x^{2} = \frac{16}{3}

Multiply both sides by

4

3 x^{2} = \frac{64}{3}

Divide both sides by

3

x^{2} = \frac{64}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{64}{9}, x = - \frac{64}{9}

\frac{64}{9} = \frac{8}{3}

- \frac{64}{9} = - \frac{8}{3}

x = \frac{8}{3}, x = - \frac{8}{3}

x^{2} - 11 x + 24 = 0

6 (y - 8)^{2} = 18

x^{2} + 6 x + 13 = 5

x^{2} + 18 x + 42

u^{2} + 20 u + 101 = 0

What are the solutions to the equation 3/4 x^2-1/3 =5 ?
The solutions to the equation 3/4 x^2-1/3 =5 are x= 8/3 ,x=-8/3
Find the zeros of 3/4 x^2-1/3 =5
The zeros of 3/4 x^2-1/3 =5 are x= 8/3 ,x=-8/3