What are the solutions to the equation u^2+20u+101=0 ?

The solutions to the equation u^2+20u+101=0 are u=-10+i,u=-10-i

Find the zeros of u^2+20u+101=0

The zeros of u^2+20u+101=0 are u=-10+i,u=-10-i

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u^{2} + 20 u + 101 = 0

u = - 10 + i, u = - 10 - i

Solution steps

u^{2} + 20 u + 101 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 101}{2 \cdot 1}

Simplify

2 0^{2} - 4 \cdot 1 \cdot 101 : 2 i

u_{1, 2} = \frac{- 20 \pm 2 i}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- 20 + 2 i}{2 \cdot 1}, u_{2} = \frac{- 20 - 2 i}{2 \cdot 1}

u = \frac{- 20 + 2 i}{2 \cdot 1} : - 10 + i

u = \frac{- 20 - 2 i}{2 \cdot 1} : - 10 - i

The solutions to the quadratic equation are:

u = - 10 + i, u = - 10 - i

t^{2} + 4 t - 17 = t

3 (x + 1)^{2} = 18

15 c^{2} - 8 c - 12 = 0

- 3 x^{2} + 15 x - 18 = 0

21 x^{2} - 13 - 20 = 0

What are the solutions to the equation u^2+20u+101=0 ?
The solutions to the equation u^2+20u+101=0 are u=-10+i,u=-10-i
Find the zeros of u^2+20u+101=0
The zeros of u^2+20u+101=0 are u=-10+i,u=-10-i