What are the solutions to the equation -3x^2+15x-18=0 ?

The solutions to the equation -3x^2+15x-18=0 are x=2,x=3

Find the zeros of -3x^2+15x-18=0

The zeros of -3x^2+15x-18=0 are x=2,x=3

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- 3 x^{2} + 15 x - 18 = 0

x = 2, x = 3

Solution steps

- 3 x^{2} + 15 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 ( - 3 ) ( - 18 )}{2 ( - 3 )}

1 5^{2} - 4 (- 3) (- 18) = 3

x_{1, 2} = \frac{- 15 \pm 3}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 15 + 3}{2 ( - 3 )}, x_{2} = \frac{- 15 - 3}{2 ( - 3 )}

x = \frac{- 15 + 3}{2 ( - 3 )} : 2

x = \frac{- 15 - 3}{2 ( - 3 )} : 3

The solutions to the quadratic equation are:

x = 2, x = 3

21 x^{2} - 13 - 20 = 0

\frac{1}{2} x^{2} + 3 x = 8

x^{2} + 12 x = - 21

m (m - 7) = - 10

(2 y - 3)^{2} = 49

What are the solutions to the equation -3x^2+15x-18=0 ?
The solutions to the equation -3x^2+15x-18=0 are x=2,x=3
Find the zeros of -3x^2+15x-18=0
The zeros of -3x^2+15x-18=0 are x=2,x=3