What are the solutions to the equation 3x^2-11x+16=0 ?

The solutions to the equation 3x^2-11x+16=0 are x= 11/6+i(sqrt(71))/6 ,x= 11/6-i(sqrt(71))/6

Find the zeros of 3x^2-11x+16=0

The zeros of 3x^2-11x+16=0 are x= 11/6+i(sqrt(71))/6 ,x= 11/6-i(sqrt(71))/6

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3 x^{2} - 11 x + 16 = 0

x = \frac{11}{6} + i \frac{71}{6}, x = \frac{11}{6} - i \frac{71}{6}

Solution steps

3 x^{2} - 11 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 3 \cdot 16}{2 \cdot 3}

Simplify

(- 11)^{2} - 4 \cdot 3 \cdot 16 : 71 i

x_{1, 2} = \frac{- ( - 11 ) \pm 71 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 71 i}{2 \cdot 3}, x_{2} = \frac{- ( - 11 ) - 71 i}{2 \cdot 3}

x = \frac{- ( - 11 ) + 71 i}{2 \cdot 3} : \frac{11}{6} + i \frac{71}{6}

x = \frac{- ( - 11 ) - 71 i}{2 \cdot 3} : \frac{11}{6} - i \frac{71}{6}

The solutions to the quadratic equation are:

x = \frac{11}{6} + i \frac{71}{6}, x = \frac{11}{6} - i \frac{71}{6}

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(x - 7) (x + 2) = 3 x^{2} - 5 x - 22

(x + 2) (x + 3) = 5 (x + 3)

What are the solutions to the equation 3x^2-11x+16=0 ?
The solutions to the equation 3x^2-11x+16=0 are x= 11/6+i(sqrt(71))/6 ,x= 11/6-i(sqrt(71))/6
Find the zeros of 3x^2-11x+16=0
The zeros of 3x^2-11x+16=0 are x= 11/6+i(sqrt(71))/6 ,x= 11/6-i(sqrt(71))/6