What are the solutions to the equation (x+2)(x+3)=5(x+3) ?

The solutions to the equation (x+2)(x+3)=5(x+3) are x=-3,x=3

Find the zeros of (x+2)(x+3)=5(x+3)

The zeros of (x+2)(x+3)=5(x+3) are x=-3,x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 2) (x + 3) = 5 (x + 3)

x = - 3, x = 3

Solution steps

(x + 2) (x + 3) = 5 (x + 3)

Move

5 (x + 3)

to the left side

(x + 2) (x + 3) - 5 (x + 3) = 0

Factor

(x + 2) (x + 3) - 5 (x + 3) : (x + 3) (x - 3)

(x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x - 3 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions to the quadratic equation are:

x = - 3, x = 3

k^{2} + 5 k - 36 = 0

x^{2} - 8 x = - 25

\frac{12 - x ^{2}}{5} = 0

5 r^{2} - 13 r + 6 = r^{2}

3 q^{2} - 116 q + 980 = 0

What are the solutions to the equation (x+2)(x+3)=5(x+3) ?
The solutions to the equation (x+2)(x+3)=5(x+3) are x=-3,x=3
Find the zeros of (x+2)(x+3)=5(x+3)
The zeros of (x+2)(x+3)=5(x+3) are x=-3,x=3