What are the solutions to the equation k^2+5k-36=0 ?

The solutions to the equation k^2+5k-36=0 are k=4,k=-9

Find the zeros of k^2+5k-36=0

The zeros of k^2+5k-36=0 are k=4,k=-9

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k^{2} + 5 k - 36 = 0

k = 4, k = - 9

Solution steps

k^{2} + 5 k - 36 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 36) = 13

k_{1, 2} = \frac{- 5 \pm 13}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 5 + 13}{2 \cdot 1}, k_{2} = \frac{- 5 - 13}{2 \cdot 1}

k = \frac{- 5 + 13}{2 \cdot 1} : 4

k = \frac{- 5 - 13}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

k = 4, k = - 9

x^{2} - 8 x = - 25

\frac{12 - x ^{2}}{5} = 0

5 r^{2} - 13 r + 6 = r^{2}

3 q^{2} - 116 q + 980 = 0

- 10 x^{2} - 5 x - 11 = 0

What are the solutions to the equation k^2+5k-36=0 ?
The solutions to the equation k^2+5k-36=0 are k=4,k=-9
Find the zeros of k^2+5k-36=0
The zeros of k^2+5k-36=0 are k=4,k=-9