What are the solutions to the equation 5r^2-13r+6=r^2 ?

The solutions to the equation 5r^2-13r+6=r^2 are r=(13+sqrt(73))/8 ,r=(13-sqrt(73))/8

Find the zeros of 5r^2-13r+6=r^2

The zeros of 5r^2-13r+6=r^2 are r=(13+sqrt(73))/8 ,r=(13-sqrt(73))/8

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5 r^{2} - 13 r + 6 = r^{2}

r = \frac{13 + 73}{8}, r = \frac{13 - 73}{8}

Decimal Notation

r = 2.69300 \dots, r = 0.55699 \dots

Solution steps

5 r^{2} - 13 r + 6 = r^{2}

Move

r^{2}

to the left side

4 r^{2} - 13 r + 6 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 4 \cdot 6}{2 \cdot 4}

(- 13)^{2} - 4 \cdot 4 \cdot 6 = 73

r_{1, 2} = \frac{- ( - 13 ) \pm 73}{2 \cdot 4}

Separate the solutions

r_{1} = \frac{- ( - 13 ) + 73}{2 \cdot 4}, r_{2} = \frac{- ( - 13 ) - 73}{2 \cdot 4}

r = \frac{- ( - 13 ) + 73}{2 \cdot 4} : \frac{13 + 73}{8}

r = \frac{- ( - 13 ) - 73}{2 \cdot 4} : \frac{13 - 73}{8}

The solutions to the quadratic equation are:

r = \frac{13 + 73}{8}, r = \frac{13 - 73}{8}

3 q^{2} - 116 q + 980 = 0

- 10 x^{2} - 5 x - 11 = 0

p^{2} + 2 p - 13 = - 3 p

y^{2} - 3 y - 2 = 0

x, p^{1} y = - x^{2} + 5 x - 4

What are the solutions to the equation 5r^2-13r+6=r^2 ?
The solutions to the equation 5r^2-13r+6=r^2 are r=(13+sqrt(73))/8 ,r=(13-sqrt(73))/8
Find the zeros of 5r^2-13r+6=r^2
The zeros of 5r^2-13r+6=r^2 are r=(13+sqrt(73))/8 ,r=(13-sqrt(73))/8